Dmitro Kuzmenko vs Bogdan Panchenko Prévia da partida | 18.12.2025
Dmitro Kuzmenko vs Bogdan Panchenko
6:30
Dmitro Kuzmenko
Bogdan Panchenko
Aposte no jogo com:
Informações e probabilidades da partida
dezembro 18 2025 06:30
Concorrência
Setka Cup
Quem ganhará?
Probabilidades por 
1:
2.1
2:
1.67
Apostar
Acima/Abaixo 77.5
Probabilidades por
Sobre:
1.83
Debaixo:
1.83
Apostar
Quem ganhará?
Dmitro Kuzmenko
44.24%
55.76%
Bogdan Panchenko
Resumo
| 1 | 2 | 3 | 4 | 5 | R | |
|---|---|---|---|---|---|---|
|
Dmitro Kuzmenko
|
-
|
-
|
-
|
-
|
-
|
0
|
|
Bogdan Panchenko
|
-
|
-
|
-
|
-
|
-
|
0
|
Cara a cara
7:30
16/12
Bogdan Panchenko
3
Dmitro Kuzmenko
1
11:00
14/12
Dmitro Kuzmenko
0
Bogdan Panchenko
3
12:00
03/12
Dmitro Kuzmenko
3
Bogdan Panchenko
2
12:00
01/12
Dmitro Kuzmenko
2
Bogdan Panchenko
3
9:00
24/11
Dmitro Kuzmenko
3
Bogdan Panchenko
2
8:00
21/11
Bogdan Panchenko
3
Dmitro Kuzmenko
1
5:30
17/11
Dmitro Kuzmenko
2
Bogdan Panchenko
3
8:30
14/11
Dmitro Kuzmenko
1
Bogdan Panchenko
3
7:30
11/11
Bogdan Panchenko
3
Dmitro Kuzmenko
2
7:30
07/11
Dmitro Kuzmenko
1
Bogdan Panchenko
3
12:00
16/12
Oleh Kurylenko
3
Dmitro Kuzmenko
1
11:00
16/12
Oleksandr Syksa
1
Dmitro Kuzmenko
3
9:30
16/12
Roman Tveritinov
3
Dmitro Kuzmenko
0
7:30
16/12
Bogdan Panchenko
3
Dmitro Kuzmenko
1
5:30
16/12
Oleksandr Ziakun
1
Dmitro Kuzmenko
3
12:30
14/12
Serhii Aristarkhov
1
Dmitro Kuzmenko
3
11:00
14/12
Dmitro Kuzmenko
0
Bogdan Panchenko
3
9:00
14/12
Andrii Lushchyk
3
Dmitro Kuzmenko
0
7:00
14/12
Volodymyr Tatarnykov
3
Dmitro Kuzmenko
0
6:00
14/12
Dmytro Prylepa
3
Dmitro Kuzmenko
0
12:30
16/12
Bogdan Panchenko
0
Oleksandr Syksa
3
10:30
16/12
Roman Tveritinov
3
Bogdan Panchenko
1
8:30
16/12
Oleksandr Ziakun
1
Bogdan Panchenko
3
7:30
16/12
Bogdan Panchenko
3
Dmitro Kuzmenko
1
6:30
16/12
Oleh Kurylenko
3
Bogdan Panchenko
2
11:00
15/12
Oleh Kurylenko
3
Bogdan Panchenko
2
9:30
15/12
Oleksandr Syksa
1
Bogdan Panchenko
3
7:30
15/12
Serhii Maliuk
2
Bogdan Panchenko
3
5:30
15/12
Roman Tveritinov
3
Bogdan Panchenko
1
12:00
14/12
Andrii Lushchyk
2
Bogdan Panchenko
3
